Answer:
1150 torr
Explanation:
We are given that some argon gas at a volume of 22.5 L has a pressure of 953 torr. We want to know what the pressure exerted by the gas is if we decrease the volume of the container to 18.7 L at a constant temperature.
Since the temperature and amount of gas is held constant, this means we will use Boyle's Law in order to find the answer.
Recall Boyle's Law: P1V1 = P2V2.
Substitute 22.5 L as V1, 953 torr as P1, and 18.7 L as V2.
22.5 L * 953 torr = 18.7 L * V2
Divide 18.7 L by both sides.
1150 torr = V2 (rounded to 3 sig figs).
