Answer:
0.77 M KCL
Explanation:
In order to find the molarity given grams and liters, you must first convert grams into moles, then divide it by the liter amount. Remember, molarity represents moles per liter.
Solving:
[tex]\[\quad \text{Mass of } \ce{KCl} = 361.2 \, \text{g}, \quad \text{Volume of water} = 6.33 \, \text{L}\][/tex]
[tex]\[\text{Molar mass of } \ce{KCl} = 39.10 \, \text{g/mol} + 35.45 \, \text{g/mol} = \boxed{74.55 \, \text{g/mol}}\][/tex]
[tex]\[\text{Number of moles of } \ce{KCl} = \frac{\text{Mass}}{\text{Molar mass}} = \frac{361.2 \, \text{g}}{74.55 \, \text{g/mol}} \approx \boxed{4.849 \, \text{moles}}\][/tex]
[tex]\[\text{Molarity (M)} = \frac{\text{Number of moles}}{\text{Volume (in liters)}} = \frac{4.849 \, \text{moles}}{6.33 \, \text{L}} \approx\boxed{ 0.766 \, \text{M}}\][/tex]
Rounded to the nearest hundredth, the correct answer would be option 4 0.77 M KCl
