yofavezane
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At a carwash, the purchases for one week are recorded in the table below:
\begin{tabular}{|l|c|c|c|}
\hline & Rinse & Wax & \begin{tabular}{c}
Rinse and \\
Wax
\end{tabular} \\
\hline SUV & 11 & 7 & 13 \\
\hline Sedan & 31 & 19 & 17 \\
\hline Van & 41 & 29 & 23 \\
\hline
\end{tabular}

If we choose a customer at random, what is the probability that they have purchased a job for a sedan or a wax?
$
P (\text { Sedan or } Wax )=\underline{[?]}
$

At a carwash the purchases for one week are recorded in the table below begintabularlccc hline amp Rinse amp Wax amp begintabularc Rinse and Wax endtabular hlin class=

Respuesta :

Answer:  103/191

Work Shown

A = 31+19+17 = 67 sedans

B = 7+19+29 = 55 cars got a wax

C = 19 sedans got a wax

A+B-C = 67+55-19 = 103 cars are either a sedan, got a wax, or both

This is out of the 11+7+13+31+19+17+41+29+23 = 191 cars total.

In short there are 103 cars we want out of 191 total.

This leads to the answer 103/191