Respuesta :

Answer:

Here,
Height of cuboid(h)=2cm
Breadth of cuboid(b)=3cm
Length of cuboid(l)=?
Area of one rectangular face=20cm^2
now,
Area of that rectangular face=l*h
or,20cm^2=l*2cm
or,l=20cm^2/2cm
or,l=10cm
then,
Surface area of cuboid=2*(lh+bh+lb)
                                    =2*(10cm*2cm+3cm*2cm+10cm*3cm)
                                    =2*(20cm^2+6cm^2+30cm^2)
                                    =2*56cm^2
                                    =112cm^2

Step-by-step explanation:

Answer:

112 cm²

Step-by-step explanation:

To find the surface area of the given cuboid, we can use the formula for the surface area of a cuboid:

[tex]\boxed{\begin{array}{l}\underline{\textsf{Surface area of a cuboid}}\\\\S.A.=2(wl+hl+hw)\\\\\textsf{where:}\\\phantom{ww}\bullet\;\textsf{$w$ is the width of the base.}\\ \phantom{ww}\bullet\;\textsf{$l$ is the length of the base.}\\ \phantom{ww}\bullet\;\textsf{$h$ is the height of the cuboid.}\end{array}}[/tex]

In this case, since the area of one side is given as 20 cm² and the height is 2 cm, then the length of the base of the cuboid is 10 cm.

Therefore:

  • w = 3 cm
  • l = 10 cm
  • h = 2 cm

Substitute the values of w, l and h into the formula and solve for SA:

[tex]S.A.=2(3\times 10+2 \times 10+2 \times 3)\\\\S.A.=2(30+20+6)\\\\S.A.=2(56)\\\\S.A.=112\; \rm cm^2[/tex]

Therefore, the surface area of the cuboid is:

[tex]\Large\boxed{\boxed{112\; \rm cm^2}}[/tex]