Here is a cuboid. Calculate the surface area of the cuboid. Show your working.

Answer:
Here,
Height of cuboid(h)=2cm
Breadth of cuboid(b)=3cm
Length of cuboid(l)=?
Area of one rectangular face=20cm^2
now,
Area of that rectangular face=l*h
or,20cm^2=l*2cm
or,l=20cm^2/2cm
or,l=10cm
then,
Surface area of cuboid=2*(lh+bh+lb)
=2*(10cm*2cm+3cm*2cm+10cm*3cm)
=2*(20cm^2+6cm^2+30cm^2)
=2*56cm^2
=112cm^2
Step-by-step explanation:
Answer:
112 cm²
Step-by-step explanation:
To find the surface area of the given cuboid, we can use the formula for the surface area of a cuboid:
[tex]\boxed{\begin{array}{l}\underline{\textsf{Surface area of a cuboid}}\\\\S.A.=2(wl+hl+hw)\\\\\textsf{where:}\\\phantom{ww}\bullet\;\textsf{$w$ is the width of the base.}\\ \phantom{ww}\bullet\;\textsf{$l$ is the length of the base.}\\ \phantom{ww}\bullet\;\textsf{$h$ is the height of the cuboid.}\end{array}}[/tex]
In this case, since the area of one side is given as 20 cm² and the height is 2 cm, then the length of the base of the cuboid is 10 cm.
Therefore:
Substitute the values of w, l and h into the formula and solve for SA:
[tex]S.A.=2(3\times 10+2 \times 10+2 \times 3)\\\\S.A.=2(30+20+6)\\\\S.A.=2(56)\\\\S.A.=112\; \rm cm^2[/tex]
Therefore, the surface area of the cuboid is:
[tex]\Large\boxed{\boxed{112\; \rm cm^2}}[/tex]