A man with dark (dominant), curly (see problem I.5.) hair marries a woman with light, straight hair. Their daughter, who happens to have dark hair, marries a man with light, wavy hair. Answer the following questions about this dark-haired daughter and her family. a. Draw a Punnett’s square for this marriage, and predict the phenotypic ratio among the offspring of the daughter and her husband. b. What is the chance that they will have a child with hair just like his or her father’s?

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Answer:

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a.

For the Punnett’s square:

Father’s genotype: Dd (dark hair)
Mother’s genotype: ll (light hair)

So the Punnett’s square would look like:

l l
D Dl Dl
d dl dl

From the Punnett’s square, we can see that all offspring will have dark hair (Dl) because dark hair (D) is dominant over light hair (l).

Phenotypic ratio among the offspring: 100% dark hair.

b. The chance of having a child with hair just like the father’s is 0%, as all offspring will inherit the dominant dark hair allele from the mother.

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