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A simple pendulum of negligible mass has a period of 2.3 s on earth. Assume the acceleration due to gravity is 9.8 m/s2. What is the approximate length of this pendulum?

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Answer:

Length of this pendulum = 1.3m

Explanation:

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MathPhys

Answer:

1.3 m

Explanation:

The period of a simple pendulum is equal to 2π times the square root of the ratio of the pendulum's length to the acceleration due to gravity.

T = 2π √(L / g)

Given T = 2.3 s and g = 9.8 m/s²:

2.3 s = 2π √(L / 9.8 m/s²)

L = 1.3 m

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