Write the equation of the line that passes through (5,-2) and is perpendicular to y=5/3x-3

Answer:
y=-3/5x+1
Step-by-step explanation:
If line A's slope=m and line B is perpendicular to line A, then line B's slope = -1/m, that is, the negative reciprocal of line A's slope.
Line A's slope = m
if Line B is perpendicular to Line A:
Line B's slope = -1/m
Since we know that the new line is perpendicular to the line with a slope of 5/3, the new line's slope is -3/5
Now we can write y = -3/5(x)+b
Since we know the perpendicular line passes through points (5,-2), we can write
-2 = -3/5(5)+b
b=1
so our new line's equation is y=-3/5x+1