Answer:
To find the least value of B such that 2100B is a perfect square, we need to determine the factors of 2100 and check if any of them can be multiplied by B to give a perfect square.
The prime factorization of 2100 is: 2^2 * 3 * 5^2 * 7.
To make 2100B a perfect square, we need to have an equal number of each prime factor. Since 2100 already has two 2's, one 3, two 5's, and one 7, we need to include an additional 2, an additional 5, and an additional 7 in the factorization of B.
Therefore, the least value of B would be 2 * 5 * 7 = 70.
So, the least value of B such that 2100B is a perfect square is 70.
