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What is the factored form of 8x³−27y³?
a. (2x−3y)(4x²−9xy+6y²)
b. (2x+3y)(4x²−9xy−6y²)
c. (2x−3y)(4x²+9xy+6y²)
d. (2x+3y)(4x²−9xy+6y²)

Respuesta :

Itz5151

Answer:

= (2x-3y)(4x²+6xy+9y²)

Step-by-step explanation:

(2x)³-(3y)³

We are clear that (a³-b³) = (a-b)(a²+ab+b²)

= (2x)³-(3y)³ = (2x-3y)((2x)²+2x*3y+(3y)²)

= (2x-3y)(4x²+6xy+9y²)

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