dayneboberg8628 dayneboberg8628

08-04-2024
Chemistry

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We wish to determine the moles of lead(II) iodide precipitated when 125 mL of 0.20 M potassium iodide reacts with excess lead(II) nitrate. 2KI(aq)+Pb(NO₃)₂(aq)to 2KNO₃(aq)+PbI₂(s) In the previous step, you determined 0.025 mol KI react. How many moles of lead(II) iodide form during the reaction?

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