Pyramid A is a square pyramid with a base side length of 14 inches and a height of 6 inches. Pyramid B has a volume of 3,136 cubic inches. How many times bigger is the volume of pyramid B than pyramid A? Give your answer as a percentage. Provide an explanation and proof for your answer to receive full credit. (10 points)

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Answer:

PLease check your answer my dear friend

Step-by-step explanation:

To find out how many times bigger the volume of Pyramid B is compared to Pyramid A, we need to compare their volumes.

The volume \(V\) of a square pyramid can be calculated using the formula:

\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

For Pyramid A, we can calculate its volume using the given dimensions:

\[ V_A = \frac{1}{3} \times (14 \text{ inches})^2 \times 6 \text{ inches} \]

\[ V_A = \frac{1}{3} \times 196 \text{ inches}^2 \times 6 \text{ inches} \]

\[ V_A = \frac{1}{3} \times 1176 \text{ cubic inches} \]

\[ V_A = 392 \text{ cubic inches} \]

Now, we'll compare this volume to the volume of Pyramid B, which is given as \(3136 \text{ cubic inches}\).

To find out how many times bigger Pyramid B is compared to Pyramid A, we divide the volume of Pyramid B by the volume of Pyramid A:

\[ \text{Times Bigger} = \frac{V_B}{V_A} = \frac{3136}{392} \approx 8 \]

So, Pyramid B is 8 times bigger in volume than Pyramid A.

To express this as a percentage increase:

\[ \text{Percentage Increase} = \left( \frac{\text{Volume of Pyramid B} - \text{Volume of Pyramid A}}{\text{Volume of Pyramid A}} \right) \times 100\% \]

\[ \text{Percentage Increase} = \left( \frac{3136 - 392}{392} \right) \times 100\% \]

\[ \text{Percentage Increase} = \left( \frac{2744}{392} \right) \times 100\% \]

\[ \text{Percentage Increase} \approx 700\% \]

So, the volume of Pyramid B is approximately 700% bigger than Pyramid A.