) A Mini starts from rest on a curved road of 280 m radius and accelerates at constant tangential acceleration of 0.72 m/s2. Compute the time and the distance for which the car will travel before the magnitude of the total acceleration attained by it becomes 0.83 m/s2.

Respuesta :

Answer:

t = 14.9 s

s = 80.3 m

Explanation:

The total acceleration is related to the tangential acceleration and the centripetal acceleration by Pythagorean's theorem. The centripetal acceleration is equal to the square of the tangential velocity divided by the radius. From there, we use kinematics to solve for time and distance traveled.

Using Pythagorean theorem:

a² = at² + ac²

0.83² = 0.72² + ac²

ac = 0.413 m/s²

The tangential velocity is:

ac = v² / r

0.413 = v² / 280

v = 10.75 m/s

Given that initial velocity u = 0 m/s, final velocity v = 10.75 m/s, and tangential acceleration is a = 0.72 m/s², the distance traveled is:

v² = u² + 2as

10.75² = 0² + 2 (0.72) s

s = 80.3 m

And the time traveled is:

v = u + at

10.75 = 0 + (0.72) t

t = 14.9 s