Answer:
a) 8.3 m/s²
b) 270 m
Explanation:
a) We can find the acceleration using the first law of motion.
v = u + at
[tex]\sf a = \dfrac{v - u}{t}[/tex]
a - acceleration
v - final velocity & v = 70 m/s
u - initial velocity & u = 20 m/s
t - time & t = 6 s
[tex]\sf a = \dfrac{70 - 20}{6}\\\\\\a = \dfrac{50}{6}\\\\\boxed{\bf a = 8.3 \ m/s^2}[/tex]
b) We can find the distance traveled using the second law of motion.
[tex]\boxed{ \bf s = ut + \dfrac{1}{2}at^2}[/tex]
[tex]\sf s = 20*6+\dfrac{1}{2}*\dfrac{50}{6}*6^2\\\\\\s = 120 + 25*6\\\\s = 120 + 150\\[/tex]
s = 270 m
The bike travelled 270 m.
