The side of a certain square is 3 feet longer than that of another square. The sum of the areas is 117 square feet. Find the dimensions of the original square.

Respuesta :

Answer:

original dimensions = 6 feet side

Step-by-step explanation:

we can represent this problem as
x^2 + (x + 3)^2 = 117

x^2 + x^2 + 6x + 9 = 117

combine like terms

2x^2 + 6x + 9 = 117

set equal to 0

2x^2 + 6x - 108 = 0

divide by 2 to simplify

x^2 + 3x - 54 = 0

factorise

(x - 6)(x + 9) = 0

x = 6, x = -9

side of square cannot be negative so x = 6