lol009
contestada

A tire company is selling two different tread patterns of tires. Tire x sells for $75.00 and tire y sells for $85.00.Three times the number of tire y sold must be less than or equal to twice the number of x tires sold. The company has at most 300 tires to sell.

What is the maximum revenue that the company can make?



$13,500

$22,500

$23,700

$25,500

Respuesta :

kinglife4688
23,700 is the revenue they can make at most
calculista

Let

x-------> the number of x tires sold

y-------> the number of y tires sold

we know that

[tex] 3y \leq 2x [/tex] ------> equation [tex] 1 [/tex]

[tex] x+y \leq 300 [/tex] ------> equation [tex] 2 [/tex]

using a graph tool

see the attached figure

the solution is the shaded area

the maximum revenue that the company can make is for the point [tex] (180,120) [/tex]

[tex] x=180\ tires\\ y=120\ tires\\ Revenue=75*180+85*120\\ Revenue=23,700 [/tex]

therefore

the answer is the option

$[tex] 23,700 [/tex]

Ver imagen calculista

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