If you add MeOH to CoCl2(Alc)2, the CoCl2(Alc)2 concentration will change. What are the two reasons for this concentration change?

The two reasons for the concentration change are as follows:
1. The chemical reaction between the two reactant shift the equilibrium of the reaction to the right thus reducing the concentration of the reactants and increasing the concentration of the product.
2. The removal of the product of the reaction will also change the concentration of the reactants.

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jamuuj jamuuj · Answer 2 · 2019-01-30T06:56:36+01:00

Answer;

The equilibrium of the equation shifts to the right
The removal of the Alc part of the CoCl2(Alc)2 during the reaction

Explanation;

The two reasons for this concentration change are;

First because the equilibrium of the equation shifts to the right thereby resulting in the reduction of the concentration of CoCl2 (Alc)2 as more ions move from the reactants to the product side. For instance, the reaction between MeOH and CoCl2(Alc)2 will result in the formation of CoCl2(MeOH)4. Ions from CoCl2(Alc)2 will be used in the reaction leading to decreased concentration of the reactants.
Secondly; because of the removal of the Alc part of the CoCl2(Alc)2 during the reaction thereby leading to a reduction in the concentration of the reactant. For instance, as shown in the equation below, two parts of Alc is removed from CoCl2(Alc)2 during the reaction: