Respuesta :
Answer:
p(4,5) = [tex]\frac{1}{36}[/tex]
Step-by-step explanation:
The sample space for distribution of two consecutive throws of a dice is:
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
There are total 36 observation.
Probability = [tex]\frac{\text{Number of favorable outcome}}{\text{Total number of observations}}[/tex]
Thus, Probability(4,5) = [tex]\frac{1}{36}[/tex]
