Respuesta :

tonb
Normal circle area is πr², which is (d/2)²π.
That makes your case 14²π divided by 2 is 196π/2=98π cm²
Area of semicircle= [tex] \pi [/tex]r²
R is radius
So half of D is the radius, which is 14cm
So the answer is= [tex] \pi [/tex] x 14²
                          = 196[tex] \pi [/tex]cm²