The equation of the circle passing through the centre (3, -2) with a radius of 5 is [tex](x-3)^2+(y+2)^2 = 25[/tex]
The formula for calculating the equation of a circle is expressed according to the equation:
[tex](x-a)^2+(y-b)^2 = r^2[/tex]
(a, b) is the centre of the circle
r is the radius of the circle
Given the following parameters
radius = 5
centre = (3, -2)
Substitute the given values into the formula
[tex](x-3)^2+(y-(-2))^2 = 5^2\\(x-3)^2+(y+2)^2 = 25[/tex]
Hence the equation of the circle passing through the centre (3, -2) with a radius of 5 is [tex](x-3)^2+(y+2)^2 = 25[/tex]
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