Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

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06-09-2017
Mathematics

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Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

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mathmate mathmate · Answer 1 · 2017-09-06T16:37:50+02:00

mathmate mathmate

06-09-2017

Since it is stretched vertically, the transformation is
(x,y) -> (x, ky) where k is the vertical scale factor = 2.5

If H(-2,0), then H' = (-2,0)->(-2,2.5*0)=(-2,0)

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stokholm stokholm · Answer 2 · 2019-05-17T09:37:38+02:00

Answer:

Step-by-step explanation:

Alright, lets get started.

The square is stretched vertically.

The scale factor is given as 2.5 = k

The point H is changes to H'

The given H is : [tex](-2, 0)[/tex]

The new stretched H' will be : [tex](-2, k *0)[/tex]

because k is the scale factor

So, new H' point will be : [tex](-2, 2.5*0) = (-2, 0)[/tex]

means the co-ordinates of H' is (-2,0) : Answer

Hope it will help :)