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A game involves rolling a number cube. You get one point if you roll an even number and negative one point if you roll an odd number. Which statements are true regarding this scenario? Check all that apply. The sample space is {1, 2, 3, 4, 5, 6}. The expected value for the game is 0. The expected value for the game is . The game is fair because the expected value is equal to 0. The game is unfair because the expected value does not equal 0.

Respuesta :

JeanaShupp

Answer: The sample space is {1, 2, 3, 4, 5, 6}.

The expected value for the game is 0.

The game is fair because the expected value is equal to 0.


Step-by-step explanation:

For rolling a dice the sample space = {1, 2, 3, 4, 5, 6}

As there are equal number of odd numbers as well as even numbers and we get one point if we roll an even number and negative one point if you roll an odd number, therefore, the expected value = 0

Therefore, the game is fair because the expected value is equal to 0.

mickymike92

Based on the laws of probability and the rules of the game, the true statements are:

  • The sample space is {1, 2, 3, 4, 5, 6}.
  • The expected value for the game is 0.
  • The game is fair because the expected value is equal to 0.

What are the true statements in the given scenario?

A number cube has six faces with six numbers 1, 2, 3, 4, 5 and 6.

Therefore, the sample space is {1, 2, 3, 4, 5, 6}.

According to the rules of the game, you get one point if you roll an even number and negative one point if you roll an odd number.

Since there are equal chances of getting even and odd numbers, expected value is equal to 0.

Therefore, the game is fair because the expected value is equal to 0.

Therefore, based on the laws of probability and the rules of the game, the true statements are:

  • The sample space is {1, 2, 3, 4, 5, 6}.
  • The expected value for the game is 0.
  • The game is fair because the expected value is equal to 0.

Learn more about probability at: https://brainly.com/question/24756209

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