Respuesta :
To answer this kind of question, you need to insert the first equation into second equation or vice versa. The equation from the question should be:
1. 3 paperback books + 5 hardcover book = $80.10
2. 7 paperback books + 4 hardcover book= $100.65
It would be easier to convert the 1st equation into
5 hardcover book = $80.10- 3 paperback books
hardcover book= $16.02- 0.6 paperback books
Then insert it to 2nd equation:
7 paperback books + 4 ($16.02- 0.6 paperback books)= $100.65
7 paperback books + $64.08- 2.4 paperback books= $100.65
4.6 paperback books = $100.65- $64.08= $36.57
paperback book= $7.95
Insert paperback book price to the first equation to find the hardcover book price
3 paperback books + 5 hardcover book = $80.10
3 ($7.95)+ 5 hardcover book = $80.10
5 hardcover book = $80.10 - $23.85= $56.25
hardcover book = $11.25
Then one paperback and one hardcoverbook= $7.95 + $11.25= $19.20
1. 3 paperback books + 5 hardcover book = $80.10
2. 7 paperback books + 4 hardcover book= $100.65
It would be easier to convert the 1st equation into
5 hardcover book = $80.10- 3 paperback books
hardcover book= $16.02- 0.6 paperback books
Then insert it to 2nd equation:
7 paperback books + 4 ($16.02- 0.6 paperback books)= $100.65
7 paperback books + $64.08- 2.4 paperback books= $100.65
4.6 paperback books = $100.65- $64.08= $36.57
paperback book= $7.95
Insert paperback book price to the first equation to find the hardcover book price
3 paperback books + 5 hardcover book = $80.10
3 ($7.95)+ 5 hardcover book = $80.10
5 hardcover book = $80.10 - $23.85= $56.25
hardcover book = $11.25
Then one paperback and one hardcoverbook= $7.95 + $11.25= $19.20
Let us represent
Paperback books = p
Hardcover books = h
Three paperback books and five hardcover books cost $80.10
3p + 5h = 80.10..........Equation 1
Seven paperback books and four hardcover books cost $100.65
7p + 4h = 100.65.......Equation 2
Step 1
We have to find the cost of each paperback and hardcover book. We do this using the Elimination Method.
3p + 5h = 80.10..........Equation 1
7p + 4h = 100.65.......Equation 2
Multiply Equation 1 by 4 and Equation 2 by 5 to eliminate h
12p + 20h = 320.4........Equation 3
35p + 20h = 503.25.......Equation 4
We subtract Equation 3 from Equation 4
23p = 182.85
We divide both sides by 23
23p/23 = 182.85/23
p = 7.95
The cost of one paperback book is $7.95
We solve for h, the cost of one hardback book by substituting 7.95 in Equation 1
3p + 5h = 80.10..........Equation 1
3(7.95) + 5h = 80.10
23.85 + 5h = 80.10
5h = 80.10 - 23.85
5h = 56.25
We divide both sides by 5
5h/5 = 56.25/5
h = 11.25
The cost of one hardback book is $11.25
Step 2
The cost of one paperback book is $7.95
The cost of one hardback book is $11.25
The total cost of one paperback and one hardcover book is
$7.95 + $11.25 = $19.20
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https://brainly.com/question/20160304