Respuesta :
x^2 – 3x – 4 = (x - 4)(x +1 )
cause
(x - 4)(x +1 ) = x^2 - 4x + x - 4 = x^2 - 3x - 4
answer
(x - 4)(x +1 ) are factors of x^2 – 3x – 4
cause
(x - 4)(x +1 ) = x^2 - 4x + x - 4 = x^2 - 3x - 4
answer
(x - 4)(x +1 ) are factors of x^2 – 3x – 4
Answer:
[tex](x+1)[/tex] and [tex](x-4)[/tex].
Step-by-step explanation:
We have been a trinomial [tex]x^2-3x-4[/tex]. We are asked to find the factors of our given trinomial.
We will use split the middle term to solve our given problem. We need to two number whose sum is [tex]-3[/tex] and whose product is [tex]-4[/tex]. We know such two numbers are [tex]-4\text{ and }1[/tex].
Split the middle term:
[tex]x^2-4x+x-4[/tex]
Make two groups:
[tex](x^2-4x)+(x-4)[/tex]
Factor out GCF of each group:
[tex]x(x-4)+1(x-4)[/tex]
[tex](x-4)(x+1)[/tex]
Therefore, factors of our given trinomial are [tex](x+1)[/tex] and [tex](x-4)[/tex].