You drive in a straight line at 20.0 m/s for 10.0 min, then at 34.0 m/s for another 10.0 min. What is the average speed?

To answer this question, you need to count the total distance traveled. The calculation would be:
Total distance = v1 * t1 + v2*t2= 20m/s * 10 min * 60 sec/min + 34 m/s * 10 min * 60 sec/min= 12000m+20400m= 32400m.

Then you need to divide the distance with the total time to find the average speed.
It would be: 32400m/ (10min+10min)= 32400m/20min * 1 min/60sec= 27m/s

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asuwafohjames asuwafohjames · Answer 2 · 2021-09-03T20:07:35+02:00

The average speed when I drive in a straight line at 20.0 m/s for 10.0 min, then at 34.0 m/s for another 10.0 min is 27 m/s

Average speed: Thes can be defined as the ratio of the total distance to the total time traveled by a body.

The question above can be solved using the formula below

S = D/T.............. Equation 1

Where S = Average speed, D = Total distance, T = total time

For the first case,

d₁ = s₁×t₁

Given: s₁ = 20 m/s, t₁ = 10 min = 10×60 = 600 s

d₁ = 20(600)

d₁ = 12000 m.

For the second case,

d₂ = s₂×t₂................ Equation 2

Given: s₂ = 34 m/s, t₂ = 10 min. = 600 s

d₂ = 34(600)

d₂ = 20400 m

Therefore,

Total distance (D) = 12000+20400

D = 32400 m

Total distance (T) = 600+600 = 1200 s

S = 32400/1200

S = 27 m/s

Hence, What is the average speed is 27 m/s

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