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Compare the acceleration of a motorcycle that accelerates from 80km/h to 90km/h with the acceleration of a bicycle thaat accelerate s from rest to 10km/h in the same time.

Respuesta :

Given for the motorcycle:



Vi = 80 km/h

Vf = 90 km/h



Given for the bicycle



Vi = 0.0 km/h

Vf = 10 km/h



*IF* the time unit is the same (let's say 10 seconds), the actual value is the SAME for each, because the change in velocity was the same for each. 10 km/h over 10 seconds.



a = [ Vf - Vi ] / t

a = [ (90 km/h) - (80 km/h) ] / (360 h)

a = [ 10 km/h ] / (360 h)

a = 0.023 km/h^2



See, same thing, bicycle or motorcycle, change is 10 km/h, over the same time period gives the same value.

The acceleration of the motorcycle and the bicycle are equal.

The given parameters;

  • initial velocity of the motorcycle, u = 80 km/hr
  • final velocity of the motorcycle, v = 90 km/hr
  • initial velocity of the bicycle, u = 0 km/hr
  • final velocity of the bicycle, v = 10 km/hr

Assuming the a constant change in time of 2 hours;

The acceleration of each of the objects is calculated as follows;

[tex]a = \frac{\Delta Velocity}{\Delta \ time}[/tex]

acceleration of the motorcycle; [tex]= \frac{90 -80}{2} = 5 \ km/hr^2[/tex]

acceleration of the bicycle;  [tex]= \frac{10 - 0}{2} = 5 \ km/hr^2[/tex]

Thus, the acceleration of the motorcycle and the bicycle are equal.

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