Respuesta :
Given for the motorcycle:
Vi = 80 km/h
Vf = 90 km/h
Given for the bicycle
Vi = 0.0 km/h
Vf = 10 km/h
*IF* the time unit is the same (let's say 10 seconds), the actual value is the SAME for each, because the change in velocity was the same for each. 10 km/h over 10 seconds.
a = [ Vf - Vi ] / t
a = [ (90 km/h) - (80 km/h) ] / (360 h)
a = [ 10 km/h ] / (360 h)
a = 0.023 km/h^2
See, same thing, bicycle or motorcycle, change is 10 km/h, over the same time period gives the same value.
Vi = 80 km/h
Vf = 90 km/h
Given for the bicycle
Vi = 0.0 km/h
Vf = 10 km/h
*IF* the time unit is the same (let's say 10 seconds), the actual value is the SAME for each, because the change in velocity was the same for each. 10 km/h over 10 seconds.
a = [ Vf - Vi ] / t
a = [ (90 km/h) - (80 km/h) ] / (360 h)
a = [ 10 km/h ] / (360 h)
a = 0.023 km/h^2
See, same thing, bicycle or motorcycle, change is 10 km/h, over the same time period gives the same value.
The acceleration of the motorcycle and the bicycle are equal.
The given parameters;
- initial velocity of the motorcycle, u = 80 km/hr
- final velocity of the motorcycle, v = 90 km/hr
- initial velocity of the bicycle, u = 0 km/hr
- final velocity of the bicycle, v = 10 km/hr
Assuming the a constant change in time of 2 hours;
The acceleration of each of the objects is calculated as follows;
[tex]a = \frac{\Delta Velocity}{\Delta \ time}[/tex]
acceleration of the motorcycle; [tex]= \frac{90 -80}{2} = 5 \ km/hr^2[/tex]
acceleration of the bicycle; [tex]= \frac{10 - 0}{2} = 5 \ km/hr^2[/tex]
Thus, the acceleration of the motorcycle and the bicycle are equal.
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