Respuesta :
It is neither.
The list of perfect squares is {1, 4, 9, 16, 25, 36, 49, 64, ...} and you can see that 55 is not listed.
The list of perfect cubes is {1, 8, 27, 64, ...} and 55 isn't listed here either
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Note: To compute the list of perfect squares, you square the set {1,2,3,...}
So
1^2 = 1
2^2 = 4
3^2 = 9
etc etc
For the perfect cubes, we cube each value from {1,2,3...}
1^3 = 1
2^3 = 8
3^3 = 27
etc etc
The list of perfect squares is {1, 4, 9, 16, 25, 36, 49, 64, ...} and you can see that 55 is not listed.
The list of perfect cubes is {1, 8, 27, 64, ...} and 55 isn't listed here either
-------------------------------------------------------
Note: To compute the list of perfect squares, you square the set {1,2,3,...}
So
1^2 = 1
2^2 = 4
3^2 = 9
etc etc
For the perfect cubes, we cube each value from {1,2,3...}
1^3 = 1
2^3 = 8
3^3 = 27
etc etc
Answer:
Neither.
Step-by-step explanation:
We are asked to classify 55.
Let us take square root of 55 to determine whether 55 is a perfect square or not.
[tex]\sqrt{55}[/tex]
[tex]\sqrt{55}=7.41619848\approx 7.42[/tex]
Since 7.42 is not an integer, therefore, 55 is not a perfect square.
Let us take cube root of 55 to determine whether 55 is a perfect cube or not.
[tex]\sqrt[3]{55}[/tex]
[tex]\sqrt[3]{55}=3.802952460\approx 3.80[/tex]
Since 3.80 is not an integer, therefore, 55 is not a perfect cube.
Therefore, 55 is neither perfect square nor perfect cube.