Respuesta :
In order to determine the mass of lead, Pb, that would have an identical volume as 20.1 g of mercury, Hg, we first get the equivalent volume of 20.1 g of mercury. This can be done by using the given density of mercury which is equal to 13.6 g/cm^3. This is shown in the following equation:
20.1 g Hg/ 13.6g/cm^3 = 1.4779 cm^3 of Hg
Consequently, we use this obtained volume which is the target volume for lead. Again, we make use of the density of the substance, in this case, lead has a density of 11.4 g/cm^3. The resulting equation is then:
11.4 g/cm^3 x 1.4779 cm^3 = 16.8485 g of Pb
Thus, the amount of lead that has an identical volume as 20.1 g of mercury is 16.8485 g Pb.
20.1 g Hg/ 13.6g/cm^3 = 1.4779 cm^3 of Hg
Consequently, we use this obtained volume which is the target volume for lead. Again, we make use of the density of the substance, in this case, lead has a density of 11.4 g/cm^3. The resulting equation is then:
11.4 g/cm^3 x 1.4779 cm^3 = 16.8485 g of Pb
Thus, the amount of lead that has an identical volume as 20.1 g of mercury is 16.8485 g Pb.
Answer: The mass of lead is 16.872 g
Explanation:
To calculate mass of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex] ......(1)
- For Mercury:
Density of mercury = [tex]13.6g/cm^3[/tex]
Mass of mercury = 20.1 g
Putting values in equation 1, we get:
[tex]13.6g/cm^3=\frac{20.1g}{\text{Volume of mercury}}\\\\\text{Volume of mercury}=1.48cm^3[/tex]
The volume of mercury is [tex]1.48cm^3[/tex] which is equal to the lead sample.
- For lead:
We are given:
Density of lead = [tex]11.4g/cm^3[/tex]
Volume of lead = [tex]1.48cm^3[/tex]
Putting values in equation 1, we get:
[tex]11.4g/cm^3=\frac{\text{Mass of lead}}{1.48cm^3}\\\\\text{Mass of lead}=16.872g[/tex]
Hence, the mass of lead is 16.872 g