we know that
The volume of the tank is equal to
[tex]V=B*h[/tex]
where
B is the area of the base of the tank
h is the deep of the tank
In this problem we have
[tex]V=1,568\ ft^{3}\\h=8\ ft[/tex]
[tex]V=B*h[/tex]
Solve for B
[tex]B=V/h[/tex]
substitute the values
[tex]B=1,568/8[/tex]
[tex]B=196\ ft^{2}[/tex] -------> area of the base of the tank
we know that
the base of the tank is a square
the area of a square is
[tex]A=x^{2}[/tex]
where
x is the length side of the square
[tex]196=x^{2}[/tex]
[tex]x=14\ ft[/tex]
therefore
the answer is
the length of each side of the base of the tank is [tex]14\ ft[/tex]
