Respuesta :
1. Add the equations to eliminate x. You already have x and -x so it would be easy to cancel them out.
2. a=b+4 and a=b-1. If a is four more than b, a must equal b+4. If a is one less than b, it must equal b-1.
3. Option A. Because the two both define variable b, they are equivalent.
4. 6a+c=70 and a+c=35. There should be 8 adults and 28 children since 8+27=35 and 6(8)+1(28)= 70
5. 25x+60=30x+10
60=5x+10
50=5x
10=x
y=25(10)+60
y=250+60
y=310
Final answer: 10 wks, $310
2. a=b+4 and a=b-1. If a is four more than b, a must equal b+4. If a is one less than b, it must equal b-1.
3. Option A. Because the two both define variable b, they are equivalent.
4. 6a+c=70 and a+c=35. There should be 8 adults and 28 children since 8+27=35 and 6(8)+1(28)= 70
5. 25x+60=30x+10
60=5x+10
50=5x
10=x
y=25(10)+60
y=250+60
y=310
Final answer: 10 wks, $310
1. add the 2 equations, since you have x and -x the x would be removed giving you y
2. a is 4 more than b = a = b+4
a is 1 less than b = a=b-1
so the first pair is correct.
3. Solve w + 11 = 3w – 15 to find the value of w, then you can use the value of w to find b
4. 3rd answer:
28 children and 7 adults
Equation 1: a + c = 35 ( 28+7 = 35)
Equation 2: 6a + c = 70 (6*7=42, 42+28 = 70)
5. 25x+60 = 30x+10
50 = 5x
x = 50/5 = 10 weeks
25(10) = 250+60 = 310 dollars
2nd answer 10 weeks, $310