Answer:
[tex](-2q^{\frac{4}{7} }) ^{4} =16q^{\frac{16}{7} }[/tex]
Step-by-step explanation:
We will use in this case the property of "power of a power"
[tex](a^{m} )^{n} =a^{m*n}[/tex]
So, in this case we have:
[tex]a=-2q; m=\frac{4}{7} ; n=4[/tex]
If we substitute
[tex](-2q^{\frac{4}{7} } )^{4} = 16q^{\frac{4}{7}*4 }= 16q^{\frac{16}{7} }[/tex]
