An empty 3.00 l bottle weighs 1.70 kg. filled with a certain wine, it weighs 4.72 kg. the wine contains 11.5% ethyl alcohol, c2h6o, by mass. how many grams of ethyl alcohol are there in 250.0 ml of this wine?
28.94 g of alcohol.
First, calculate the mass of 3.00 l of wine.
4.72 kg = 1.70 kg = 3.02 kg
Now calculate the mass of 250.0 ml of the wine. Using ratios will work for this
(3020 g)/(3000 ml) = (X g)/(250 ml)
Multiply both sides by 250 ml
(3020 g * 250 ml) / (3000 ml) = X
(755000 ml g) / (3000 ml) = X
251.667 g = X
So 250.0 ml of wine has a mass of 251.667 g
Now multiply by 0.115 to get the mass of alcohol
251.667 g * 0.115 = 28.94 g
