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To arrive at an answer in units of carbon atoms, first we must cancel out the grams by diving 84.3g C2H2 by the molar mass of C2H2 (26.038g/mol). This molar mass is calculated by adding the masses of 2 carbon atoms (12.011g/mol) and 2 hydrogen atoms (1.008g/mol). This renders units of moles of ethyne. Next multiply by Avagadro's number (6.022x10^23 atoms/mol) to cancel the moles of ethyne and reach atoms of ethyne. Finally, because there are 2 carbon atoms in C2H2, multiply by 2 atoms Carbon/1 atom C2H2 to reach the final answer of 3.90x10^24 atoms of Carbon. This answer has been rounded to three significant figures because the lowest known value of significant figures throughout the calculations was three (84.3). The entire process is as follows: 84.3g C2H2 x (1 mol C2H2)/(26.038 g C2H2) x (6.022x10^23 atoms C2H2)/(1 mol C2H2) x (1 atoms C2H2)/(2 atom C) = 3.90x10^24 atoms C

Taking into account the definition of avogadro's number,  1.95×10²⁴ atoms are present in 84.3 g of ethyne.  

Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

So, first of all you need to know how many moles of ethyne 84.3 g contains. Since the molar mass of C₂H₂ is 26 g / mole (that is, the more that one mole of the substance contains), the following rule of three can be applied: if 26 g are contained in 1 mole, 84.3 g are contained in how many moles of the compound?

[tex]amount of moles=\frac{84.3 gx1 mole}{26 g}[/tex]

amount of moles= 3.24 moles

Now you can apply the following rule of three: if  1 mole of ethyne contains 6.023×10²³ atoms, then 3.24 moles of the compound how many atoms does it contain?

[tex]amount of atoms=\frac{3.24 molesx6.023x10^{23} atoms}{1 mole}[/tex]

amount of atoms= 1.95×10²⁴ atoms

Finally, 1.95×10²⁴ atoms are present in 84.3 g of ethyne.  

Learn more about Avogadro's Number:

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