The whale's travelling distance is 35 m
Acceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration (m / s²)
v = final velocity (m / s)
u = initial velocity (m / s)
t = time taken (s)
d = distance (m)
Let us now tackle the problem!
Given:
acceleration = a = 0.080 m/s²
initial velocity = u = 1.0 m/s
final velocity = v = 2.57 m/s
Unknown:
distance = d = ?
Solution:
[tex]v^2 = u^2 + 2ad[/tex]
[tex]2.57^2 = 1.0^2 + 2(0.080)d[/tex]
[tex]6.6049 = 1 + 0.16d[/tex]
[tex]6.6049 - 1 = 0.16d[/tex]
[tex]0.16d = 5.6049[/tex]
[tex]d = 5.6049 / 0.16[/tex]
[tex]\large {\boxed {d \approx 35 ~ m} }[/tex]
Suppose the whale travels in a straight line, then the whale's travelling distance is 35 m
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel
