final position based on intial conditions.
xf = xo + vxo * t
yf = yo + vyo * t - (1/2) * g * t^2
xo = 0.0 ft , yo = 7.0 ft
xB = 25 ft , yB = ??? (height B jumps)
xH = 30 ft , yH = 10 ft (hoop)
initial velocity
Vxo = Vcos30; Vyo = Vsin30
gravity: g = 32.2 ft down (thus minus sign in y equation
To SCORE:
xf = 30 ft; yf = 10 ft
solve
xf and yf equations for V and t.
... this gets time in air to go 30 ft.
For Blocker
time to Blocker is: (25/30) tH (tH = time to hoop)
substitute this time into yf equation to get yf of person B.
alternate:
you should have a trajectory equation in your textbook.
y as a function of x, Vo and initial angle.
no time is needed (basically doing what i have outlined above).
