The solutions to the equation are [tex] \frac{1 +/- \sqrt{43}}{6} [/tex].
You can find the answer to any quadratic by using the quadratic formula. The formula is below.
[tex] \frac{-b +/- \sqrt{b^{2}-4ac}}{2a} [/tex]
Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.
[tex] \frac{2 +/- \sqrt{-2^{2}-4(6)(-7)}}{2(6)} [/tex]
[tex] \frac{2 +/- \sqrt{4 + 168}}{12} [/tex]
[tex] \frac{2 +/- \sqrt{172}}{12} [/tex]
[tex] \frac{1 +/- \sqrt{43}}{6} [/tex]
