Carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas. If Carlos exerts 2,000 N of force to pull the rope, and the rope is at an angle of 15° to the road, how much work did he do? Round your answer to two significant figures.

Respuesta :

5.8 × 104 J
i already checked it on edge

Answer: [tex]5.8\cdot 10^4 J[/tex]

Explanation:

The work done by Carlos is given by:

[tex]W=Fdcos\theta[/tex]

where

F is the force exerted by Carlos

d is the distance through which the car has been pulled

[tex]\theta[/tex] is the angle between the direction of the force and the motion of the car

In this problem, [tex]F=2000 N, d=30 m, \theta=15^{\circ}[/tex]. By substituting these numbers into the formula, we find

[tex]W=(2,000 N)(30 m)(cos 15^{\circ})=57,956 J=5.8\cdot 10^4 J[/tex]