Answer:
The equation of new line is (y-3)=2(x-10).
Step-by-step explanation:
If a line passing through the point (x₁,y₁) with slope m, then the point slope form of the line is
[tex](y-y_1)=m(x-x_1)[/tex]
It is given that Alejandra correctly wrote the equation
[tex](y-3)=(x-10)[/tex]
Here,
[tex]m=1,x_1=10,y_1=3[/tex]
It means the slope of the line is 1 and the line passing through the point (10,3).
The teacher then changed the line so it had a slope of 2, but still went through the same point.
Now the slope of line is 2 and the line passing through the point (10,3). So the point slope form of the line is
[tex](y-3)=2(x-10)[/tex]
Therefore the equation of new line is (y-3)=2(x-10).
