Respuesta :
14. B Add the equations
Since the equations have x and -x, if you add, it cancels out to 0 and x will be eliminated.
15. 7 weeks, $230 D
30x+20=20x+90
10x+20=90
10x=70
x=7
Plug x in
y=20(7)+90
y=140+90
y=230
16. B
4a+c= 60
a+c=27
16 children and 11 adults since 11+16=27 and 4(11)+16= 44+16=60
Since the equations have x and -x, if you add, it cancels out to 0 and x will be eliminated.
15. 7 weeks, $230 D
30x+20=20x+90
10x+20=90
10x=70
x=7
Plug x in
y=20(7)+90
y=140+90
y=230
16. B
4a+c= 60
a+c=27
16 children and 11 adults since 11+16=27 and 4(11)+16= 44+16=60
Answer:
14) Add the equations to eliminate x.
15)7 weeks, $230
16)11 children and 16 adults
Equation 1: a + c = 27
Equation 2: 4a + c = 60
Step-by-step explanation:
14) To find x and y in the given equations :
y = x + 20
y = –x + 2
Our first step will be to add the two equations so that x is eliminated and we can find y . The option
Add the equations to eliminate x is the correct option.
15) The given equations are Katie
y = 30x + 20
Pamela
y = 20x + 90
y represents the amount of money in dollars and x represents the amount of time in weeks ,
Using substitution method we have :
30x+20=20x+90
Or 30x-20x=90-20
10x=70 or
x=7 .
Substituting x value in y=30x+20 we have:
y=30(7)+20
y= 210+20
y=230.
The correct option is 7 weeks, $230.
16) It is given the total number of adults (a) and children (c) is 27,
or a+c=27.
Given zoo train ride costs $4 per adult and $1 per child,
Or 4a+c=60.
Subtracting the two equations we have:
4a+c=60
a+c=27
- - -
....................................
3a =33,
Or a=11.
Substituting a value in a+c=27
11+c=27
or c=16.
The correct option is
11 children and 16 adults
Equation 1: a + c = 27
Equation 2: 4a + c = 60