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A golfer is teeing off on a 170.0m long par three hole. The ball leaves with a velocity of 40.0m/s at 50.0 degrees to the horizontal. Assuming that she hits the ball on a direct path to the hole, how far from the hole will the ball land (assuming no bounces or rolls)?

Respuesta :

Answer:

d = 9.4 m

Explanation:

As we know that the golfer hits the ball with speed 40 m/s at an angle of 50 degree

so here we will have range of the ball on the ground is given as

[tex]R = \frac{v^2 sin2\theta}{g}[/tex]

so we will have

[tex]R = \frac{40^2 sin(2\times 50)}{9.81}[/tex]

[tex]R = 160.6 m[/tex]

So it will land at distance of 160.6 m

so the distance from the hole is given as

[tex]d = 170 - 160.6[/tex]

[tex]d = 9.4 m[/tex]

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