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what is the fewest number of distinct points that must be graphed on a number line, in order to represent natural numbers, whole numbers, integers, rational numbers, irrational numbers, and real numbers?

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nobillionaireNobley
All natural numbers are whole numbers.

All whole numbers are integers.

All integers are rational numbers.

Thus one point can be used to represent the natural numbers, the whole numbers, the integers and the rational numbers while another point represent the irrational numbers.

The real numbers are made up of the rational and the irrational numbers.

Therefore, the fewest number of distinct points that must be graphed on a number line, in order to represent natural numbers, whole numbers, integers, rational numbers, irrational numbers, and real numbers is 2 points.
MrRoyal

There are several types of numbers; and they are:

  1. Natural numbers
  2. Whole numbers
  3. Integers
  4. Rational numbers
  5. Irrational number
  6. Real numbers

The fewest number of distinct points that must be graphed on a number line is 2.

In the above list:

Except irrational numbers, all other numbers are real numbers, and the relationship between them is as follows:

Real numbers [tex]\to[/tex] Rational numbers [tex]\to[/tex] Integers [tex]\to[/tex] Whole numbers [tex]\to[/tex] Natural numbers.

This means that 1 natural number can be used to represent the other numbers (real, rational, integer and whole numbers).

Similarly, 1 number can be used to represent the irrational numbers.

So, the fewest number (n) that can be used is:

n = 1 natural number + 1 irrational number

[tex]n= 1+1[/tex]

[tex]n=2[/tex]

Hence, the fewest number of distinct points that must be graphed on a number line is 2.

Read more about numbers at:

https://brainly.com/question/17429689

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