Respuesta :

15% solution  = 150 g / liter

Molarity = 150 / 58.44 =  2.57

2.57 M is the molarity of a 15% solution of sodium chloride (NaCl) if the molecular weight of NaCl is 58.44 g/mol.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

15% solution  = 150 g / liter

Molarity = 150 ÷ 58.44 =  2.57 M

Hence, 2.57 M is the molarity of a 15% solution of sodium chloride (NaCl) if the molecular weight of NaCl is 58.44 g/mol.

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