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During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300m/s^2 ( about 30 times free-fall acceleration called 30g). The fuel burned for 8.0 s. Find the height of the Terrier-Sandhawk rocket at the end of fuel burn.

Respuesta :

Initial launch velocity, u = 0
Acceleration, a = 300 m/s²
Duration, t = 8.0 s

The distance traveled is
h = ut + (1/2)*a*t²
   = (0 m/s)*(8 s) + 0.5*(300 m/s²)*(8 s)²
   =  9600 m

Answer: 9600 m

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