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Consider the balanced chemical equation,

MgCl2(aq) + 2AgF(aq) → 2AgCl(s) + MgF2(aq)


If both reactants are completely consumed and we produce 20 formula units of AgCl, how many ions of Mg and F did we start with?

A) 10 ions of Mg and 20 ions of F

B) 10 ions of Mg and 10 ions of F

C) 20 ions of Mg and 10 ions of F

D) 20 ions of Mg and 20 ions of F

Respuesta :

kenmyna

  The number   of  ions   of Mg  and F  that   started is

 10 ions  of Mg  and 20   ions    of F  ( answer A)

Explanation

MgCl2 (aq)  + 2 AgF(aq) →  2AgCl(s)  + MgF2 (aq)


from equation  above  the  mole  ratio  of MgCl2  :AgCl  is 1 :2 therefore the number  of Mg ions  =  20  x 1 /2  = 10  ions


The   mole ratio  of  AgF: AgCl is  2:2  therefore  the  number  of F ions

  =20 ion  x2/2  = 20  ions

Becky81

Answer:

10 ions of Mg and 20 ions of F

Explanation:

In the balanced equation, one ion of Mg ends up reacting with 2 fluoride ions.The ratio 1:2 matches ups with 10 Mg to 20 F.

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