acurry474
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DeAnna has 4 quarters 3 dimes and 3 nickels in her purse. she reaches into her purse and randomly grabs two coins one at a time. what is the probability DeAnna will first grab a quarter and then without replacing it grab a nickel?

Respuesta :

musiclover10045

4+3+3 = 10 coins total

4 quarters so a 4/10 ( reduces to 2/5) probability of getting a quarter first

 then there would be 9 coins left, 3 are nickels so a 3/9 ( reduced to 1/3) probability of getting a nickel


2/5 x 1/3 = 2/15 probability for both to happen

lyndalau86

Answer:

2/15

Step-by-step explanation:

If she has 4 quarters, 3 dimes and 3 nickels, she has 10 coins in her purse.

She will get two coins, one at a time, we need to find the probability that the first one is a quarter, this would be 4/10 (positive outcomes / total possible outcomes).

Now, she needs to choose a nickel from the 9 remaining coins. This will be: 3/9 ( positive outcomes/ total possible outcomes)

We are going to multiply both probabilities because she needs to get a quarter AND a nickel:

4/10 x 3/9 = 12/90 = 6/45 = 2/15 = 2/15

The probability will be 2/15

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