[tex]4^2 = 16,right? [/tex]
[tex]p = 8,right? [/tex]
Your [tex]problem[/tex] becomes ↓
[tex] \frac{16}{8(3)} [/tex]
[tex]8(3) = 24 , right ?[/tex]
Your [tex]problem[/tex] becomes → [tex] \frac{16}{24} [/tex]
Reverse: [tex]4^2 [/tex] to [tex]2^4[/tex] they both give you an outcome of [tex]16[/tex]
Since your [tex]denominator [/tex] is [tex]24[/tex] we have to find the factor of it (you don't have do this method by the way!) [tex]2^3(3)[/tex]
Now we can do the other step!
[tex] \frac{16}{2^3(3)} [/tex] would give you the [tex]answer [/tex] of [tex] \frac{2}{3} [/tex]
But, [tex] \frac{2}{3} [/tex] as a [tex]decimal [/tex] would be [tex]0.67 [/tex]
[tex]Fraction: \frac{2}{3} \\ \\ Decimal: 0.67 [/tex]
Good luck on your assignment and enjoy your day
~[tex]MeIsKaitlyn:)[/tex]
