Answer:
The points are (8,0) and (9, 0)
Step-by-step explanation:
Given the function
[tex]f(x)=(x-8)(x-9)[/tex]
we have to find the point which is an x-intercept of the quadratic function.
X-intercept is the x-coordinate of a point where a graph of function intersects the x-axis i.e the value of x at which the value of y is 0.
Hence, to find x-intercept we have to put the value of y=0 in f(x)
[tex](x-8)(x-9)=0[/tex]
Using zero product property
⇒ [tex](x-8)=0\text{ or }(x-9)=0[/tex]
[tex]x=8\text{ or }x=9[/tex]
The points are (8,0) and (9, 0)
