Which quadratic function has a leading coefficient of 2 and a constant term of –3? f(x) = 2x3 – 3 f(x) = –3x2 – 3x + 2 f(x) = –3x3 + 2 f(x) = 2x2 + 3x – 3

Respuesta :

coefficient of 2 and a constant term of –3

answer is

f(x) = 2x^3 – 3

Answer:

[tex]f(x)=2x^{3} -3[/tex]

[tex]f(x)=2x^{2}+3x-3[/tex]

Step-by-step explanation:

Verify each case

case A) we have

[tex]f(x)=2x^{3} -3[/tex]

The leading coefficient is [tex]2[/tex]

The constant term is [tex]-3[/tex]

case B) we have

[tex]f(x)=-3x^{2} -3x+2[/tex]

The leading coefficient is [tex]-3[/tex]

The constant term is [tex]2[/tex]

case C) we have

[tex]f(x)=-3x^{3}+2[/tex]

The leading coefficient is [tex]-3[/tex]

The constant term is [tex]2[/tex]

case D) we have

[tex]f(x)=2x^{2}+3x-3[/tex]

The leading coefficient is [tex]2[/tex]

The constant term is [tex]-3[/tex]