While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. How much time does it take?

1.00 s

2.50 s

4.00 s

4.50 s

none of the above

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Аноним Аноним · Answer 1 · 2017-09-09T03:12:27+02:00

Distance = Velocity * time ----> time = distance / velocity = 60 m / 15 m/s = 4 seconds
Answer: C

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jainveenamrata jainveenamrata · Answer 2 · 2022-07-22T11:29:54+02:00

The time taken by the car will be 4 seconds. Then the correct option is D.

Let a be the acceleration, u be the initial velocity, v be the final velocity, and t be the time.

Then the equation of motion is given as,

v = u + at

v² = u² + 2as

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m.

Then the time taken by the car will be,

u = 12 m/s

v = 18 m/s

s = 60 m

Put these in the equation v² = u² + 2as.

18² = 12² + 2 x a x 60

a = 1.5

Then the time will be

18 = 12 + 1.5t

1.5t = 6

t = 4 seconds

Then the correct option is D.

More about the equation of motion link is given below.

https://brainly.com/question/13514745

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