contestada



What is the distance between the points (21, -30) and (3, 8)? If necessary, round your answer to two decimal places.

A. 56 units
B. 38 units
C. 33.47 units
D. 42.05 units

Respuesta :

dpokharnaotzjgn
To find the distance, you must know Pythagorean Theorem. Here is how to solve it:

First find the positive distance between the x's: 21-3=18
Then find the positive distance between the y's: 8-(-30)=38
Then use Pythagorean Theorem: (18)^2+(38)^2=(x)^2
After solving you get x is about 42.05 which is D

Answer:

The correct option is D.

Step-by-step explanation:

The distance between two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is defined as

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using distance formula, the distance between two points (21, -30) and (3, 8) is

[tex]d=\sqrt{(3-21)^2+(8-(-30))^2}[/tex]

[tex]d=\sqrt{(-18)^2+(38)^2}[/tex]

[tex]d=\sqrt{1768}[/tex]

[tex]d=42.0475920833[/tex]

[tex]d\approx 42.05[/tex]

The distance between the points (21, -30) and (3, 8) is 42.05 units. Therefore the correct option is D.

Otras preguntas