Tv screens are measured on the diagonal. if we have a tv-cabinet that is 64 inches long and 52 inches high, how large a tv could we put in the space (leave 2-inches on all sides for the edging of the tv)

Basically, we are to find the area of the television screen. Because a TV is rectangular in form, the formula for the area is written below:

A = L×W

The given dimensions are 64 inches in length and 52 inches in width. But that includes the edges. To compute for the screen area only, we subtract 4 inches (2 inches on both sides) to each dimension.

A = (64 - 2)(52 - 2)
A = 3,100 square inches

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ApusApus ApusApus · Answer 2 · 2019-09-18T11:52:36+02:00

Answer:

76.84 inches.

Step-by-step explanation:

We have been given that a TV -cabinet is 64 inches long and 52 inches high.

After leaving 2 inches on all sides, our new dimensions would be:

Length: [tex]64-2-2=64-4=60[/tex]

Height: [tex]52-2-2=52-4=48[/tex]

Now, we need to find diagonal of the television using Pythagoras theorem.

[tex]\text{Diagonal}^2=60^2+48^2[/tex]

[tex]\text{Diagonal}^2=3600+2304[/tex]

[tex]\text{Diagonal}^2=5904[/tex]

Take square root of both sides:

[tex]\text{Diagonal}=\sqrt{5904}[/tex]

[tex]\text{Diagonal}=76.83749[/tex]

[tex]\text{Diagonal}\approx 76.84[/tex]

Therefore, we could put a 76.84 inches TV.